![]() OB is the perpendicular bisector of the chord RS and it passes through the center of the circle. In the above circle, OA is the perpendicular bisector of the chord PQ and it passes through the center of the circle. In the above circle, if the radius OB is perpendicular to the chord PQ then PA = AQ.Ĭonverse: The perpendicular bisector of a chord passes through the center of a circle. Theorem: A radius or diameter that is perpendicular to a chord divides the chord into two equal parts and vice versa. Geometry Problem 1521 and a Thematic Poem. Geometry Problem 1527: Discovering the Hidden Angle: Solving the Puzzle of Two Intersecting Circles. ![]() Scroll down the page for examples, explanations, and solutions.Ī chord is a straight line joining 2 points on the Geometry Problem 1531: Discover How to Calculate the Length of a Chord in a Circle with Diameter Intersection and an Angle between the Diameter and Chord - A High School Challenge. The following diagrams give a summary of some Chord Theorems: Perpendicular Bisector andĬongruent Chords. If two chords in a circle are congruent, then they determine two central angles that are congruent. ![]()
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